Methanol → Benzoic acid, 4-(1-pyrrolidinylcarbonyl)-

Participants

Reaction Steps

29.0 g (0.146 mol) of monomethyl terephthalate chloride was reacted with 14.2 g (200 mmol) of pyrrolidine and 21.0 g (208 mmol) of triethylamine in 350 ml of dichloromethane. After the treatment in an ordinary manner, methyl 4-(1-pyrrolidylcarbonyl)benzoate was obtained. 29.0 g of the ester was hydrolyzed with 12.0 g of sodium hydroxide in a mixed solvent comprising 70 ml of water, 70 ml of methanol and 70 ml of tetrahydrofuran. After the completion of the reaction, the solvent was evaporated. 1 N hydrochloric acid was added to the residue and the obtained mixture was treated with dichloromethane as the extraction solvent in an ordinary manner to obtain the title compound.

Provenance & Evidence