HRID2418597

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID10868

Dicyclohexylcarbodiimide

C13H22N2

HCID75771

1-Hydroxybenzotriazole

C6H5N3O

结构：CC(C)(C)OC(=O)N1CCC[C@H]1C(=O)N[C@H](Cc1c[nH]c2ccccc12)C(=O)N[C@@H](Cc1ccccc1)C(=O)O

HCID131713758

未命名化合物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@H](N)CCCCNC(=O)OC(C)(C)C)C(N)=O

HCID131713784

未命名化合物

PRODUCTS

生成物

结构：CSCC[C@H](NC(=O)[C@H](CC(C)C)NC(=O)[C@@H](CCCCNC(=O)OC(C)(C)C)NC(=O)[C@H](Cc1ccccc1)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@@H]1CCCN1C(=O)OC(C)(C)C)C(N)=O

HCID131713785

未命名化合物

收率 46%

PROCEDURE

实验过程

Condensation of BocPro-DTrp-PheOH (0.88 g.) and HDLys(Boc)-Leu-MetNH2 (0.68 g.) using dicyclohexylcarbodiimide and 1-hydroxybenzotriazole gave BocPro-DTrp-Phe-DLys(Boc)-Leu-MetNH2 in 46% yield. De-t-butoxycarbonylation of BocPro-DTrp-Phe-DLys(Boc)-Leu-MetNH2 (560 mg.) using trifluoroacetic acid in dimethyl sulfide and ethanedithiol gave HPro-DTrp-Phe-DLys-Leu-MetNH2, which was isolated as the amorphous white solid phosphate (1:1) acetate (1:3) salt in 26% yield.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-00884829127a410198d9834ab176b237
来源数据集: uspto-grants-1984_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04472305
来源说明: uspto-grants-1984_09

反应 SMILES

[N:1]1([C:34]([O:36][C:37]([CH3:40])([CH3:39])[CH3:38])=[O:35])[CH2:33][CH2:32][CH2:31][C@H:2]1[C:3]([NH:5][C@@H:6]([C:17]([NH:19][C@H:20]([C:28](O)=[O:29])[CH2:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1)=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4].[NH2:41][C@@H:42]([C:55]([NH:57][C@H:58]([C:63]([NH:65][C@H:66]([C:71]([NH2:73])=[O:72])[CH2:67][CH2:68][S:69][CH3:70])=[O:64])[CH2:59][CH:60]([CH3:62])[CH3:61])=[O:56])[CH2:43][CH2:44][CH2:45][CH2:46][NH:47][C:48]([O:50][C:51]([CH3:54])([CH3:53])[CH3:52])=[O:49].C1(N=C=NC2CCCCC2)CCCCC1.ON1C2C=CC=CC=2N=N1>>[N:1]1([C:34]([O:36][C:37]([CH3:40])([CH3:39])[CH3:38])=[O:35])[CH2:33][CH2:32][CH2:31][C@H:2]1[C:3]([NH:5][C@@H:6]([C:17]([NH:19][C@H:20]([C:28]([NH:41][C@@H:42]([C:55]([NH:57][C@H:58]([C:63]([NH:65][C@H:66]([C:71]([NH2:73])=[O:72])[CH2:67][CH2:68][S:69][CH3:70])=[O:64])[CH2:59][CH:60]([CH3:62])[CH3:61])=[O:56])[CH2:43][CH2:44][CH2:45][CH2:46][NH:47][C:48]([O:50][C:51]([CH3:53])([CH3:54])[CH3:52])=[O:49])=[O:29])[CH2:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1)=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4]