HRID2418623

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID10868

Dicyclohexylcarbodiimide

C13H22N2

HCID75771

1-Hydroxybenzotriazole

C6H5N3O

结构：CC(C)(C)OC(=O)N1CCC[C@H]1C(=O)N[C@H](Cc1c[nH]c2ccccc12)C(=O)N[C@@H](Cc1ccccc1)C(=O)O

HCID131713758

未命名化合物

结构：CCCC[C@@H](C(N)=O)N(C)C(=O)[C@H](CC(C)C)NC(=O)[C@H](N)Cc1c[nH]c2ccccc12

HCID131713815

未命名化合物

PRODUCTS

生成物

结构：CCCC[C@@H](C(N)=O)N(C)C(=O)[C@H](CC(C)C)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@H](Cc1ccccc1)NC(=O)[C@@H](Cc1c[nH]c2ccccc12)NC(=O)[C@@H]1CCCN1C(=O)OC(C)(C)C

HCID131713816

未命名化合物

收率 64%

PROCEDURE

实验过程

Condensation of BocPro-DTrp-PheOH (part B of Example 17, 0.700 g.) and HDTrp-Leu-MeNleNH2 (0.520 g.) using dicyclohexylcarbodiimide and 1-hydroxybenzotriazole gave BocPro-DTrp-Phe-DTrp-Leu-MeNleNH2 in 64% yield. De-t-butoxycarbonylation of BocPro-DTrp-Phe-DTrp-Leu-MeNleNH2 (0.750 g.) using trifluoroacetic acid in dimethyl sulfide and ethanedithiol gave HPro-DTrp-Phe-DTrp-Leu-MeNleNH2, which was isolated as the amorphous white solid phosphate (1:1) salt tetrahydrate in 30% yield.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-d05485c3a7a74a2aa5ca981c75e9a21a
来源数据集: uspto-grants-1984_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04472305
来源说明: uspto-grants-1984_09

反应 SMILES

[N:1]1([C:34]([O:36][C:37]([CH3:40])([CH3:39])[CH3:38])=[O:35])[CH2:33][CH2:32][CH2:31][C@H:2]1[C:3]([NH:5][C@@H:6]([C:17]([NH:19][C@H:20]([C:28](O)=[O:29])[CH2:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1)=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4].[NH2:41][C@@H:42]([C:53]([NH:55][C@H:56]([C:61]([N:63]([CH3:72])[C@H:64]([C:69]([NH2:71])=[O:70])[CH2:65][CH2:66][CH2:67][CH3:68])=[O:62])[CH2:57][CH:58]([CH3:60])[CH3:59])=[O:54])[CH2:43][C:44]1[C:52]2[C:47](=[CH:48][CH:49]=[CH:50][CH:51]=2)[NH:46][CH:45]=1.C1(N=C=NC2CCCCC2)CCCCC1.ON1C2C=CC=CC=2N=N1>>[N:1]1([C:34]([O:36][C:37]([CH3:40])([CH3:39])[CH3:38])=[O:35])[CH2:33][CH2:32][CH2:31][C@H:2]1[C:3]([NH:5][C@@H:6]([C:17]([NH:19][C@H:20]([C:28]([NH:41][C@@H:42]([C:53]([NH:55][C@H:56]([C:61]([N:63]([CH3:72])[C@H:64]([C:69]([NH2:71])=[O:70])[CH2:65][CH2:66][CH2:67][CH3:68])=[O:62])[CH2:57][CH:58]([CH3:59])[CH3:60])=[O:54])[CH2:43][C:44]1[C:52]2[C:47](=[CH:48][CH:49]=[CH:50][CH:51]=2)[NH:46][CH:45]=1)=[O:29])[CH2:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1)=[O:18])[CH2:7][C:8]1[C:16]2[C:11](=[CH:12][CH:13]=[CH:14][CH:15]=2)[NH:10][CH:9]=1)=[O:4]