Hydrochloric Acid → 3-Amino-3-(4-methoxyphenyl)-2-methyl-thioacrylamide

Participants

Reaction Steps

Add HCl (4 N in dioxane, 659 mL, 2.640 mmol) to a solution of 3-amino-3-(4-methoxyphenyl)-2-methylacrylonitrile (24.8 g, 132 mmol), thioacetamide (19.8 g, 264 mmol) and dioxane (132 mL) under dry nitrogen. Stir for 2 h. Evaporate, dilute the solid with dioxane (20 mL) and add dry TEA (40 mL). Add satd K2CO3 and extract with EtOAc. Evaporate the organic solution and crystallize from CHCl3/hexane (95/5); then recrystallize from MeOH/H2O to remove the excess thioacetamide to afford 3-amino-3-(4-methoxyphenyl)-2-methyl-thioacrylamide. Yield: 90.8%.

Provenance & Evidence