Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2424300Generated: November 3, 2026

Sodium Fluoride → HCID 22940130, compound

https://huagongshe.com/reaction/2424300

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium FluorideHCID 5235—
ReactantEthyl AcetateHCID 8857—
ReactantAllyltributylstannaneHCID 90628—
Reactant6-Chloro-4-methoxy-3-(2-methylphenoxy)pyridazineHCID 22940136—
CatalystHCID 178418397HCID 178418397—
SolventWaterHCID 962—
SolventTolueneHCID 1140—
ProductHCID 22940130HCID 2294013030.5%

Reaction Steps

In toluene (4 mL) was dissolved 200 mg (0.797 mmol) of 6-chloro-4-methoxy-3-(2-methylphenoxy)pyridazine obtained in Example 2 (1), 305 mg (0.921 mmol) of allyl(tributyl)tin, and then, 96.8 mg (0.0838 mmol) of tetrakis(triphenylphosphine)palladium were successively added to the solution at room temperature, and the resulting mixture was refluxed for 3 hours and 20 minutes. The reaction mixture was allowed to stand at room temperature overnight, and then, ethyl acetate, water and sodium fluoride were added to the mixture and the resulting mixture was stirred for 2 hours. The mixture was filtered through Celite, ethyl acetate was added to the filtrate, then the organic layer was separated, and washed successively with water and brine. After drying over anhydrous sodium sulfate, the solvent was removed. The obtained residue was purified by silica gel column chromatography (hexane:ethyl acetate, gradient) to obtain 62.1 mg (0.243 mmol, Yield: 30.5%) of 6-allyl-4-methoxy-3-(2-methylphenoxy)pyridazine.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07964531B2
Source datasetuspto-grants-2011_06
ORD IDord-574778442c5148fbabe96563aab1072a
Source noteuspto-grants-2011_06