HRID242471

反应详情

EQUATION

反应方程式

HRID 242471 的结构方程式

REACTANTS

反应物

2

结构：CC=O

Acetaldehyde

C2H4O

结构：CNC(=O)[C@@H](NC(=O)n1nc(-c2cc(F)ccc2F)c2c1CCN(C)C2)C(C)(C)C

未命名化合物

PRODUCTS

生成物

1

结构：CCN1CCc2c(c(-c3cc(F)ccc3F)nn2C(=O)N[C@H](C(=O)NC)C(C)(C)C)C1

未命名化合物

PROCEDURE

实验过程

Compound 65 was prepared according to the procedure described for the synthesis of compound 64 by replacing formaldehyde with acetaldehyde. LCMS (+ESI) m/z=434.3 [M+H]+.