HRID242485

反应详情

EQUATION

反应方程式

HRID 242485 的结构方程式

REACTANTS

反应物

2

结构：C=O

Formaldehyde

CH2O

结构：CN1CCc2c(c(-c3cc(F)ccc3F)nn2C(=O)N[C@H](C(=O)O)C(C)(C)C)C1

未命名化合物

PRODUCTS

生成物

1

结构：CCN1CCc2c(c(-c3cc(F)ccc3F)nn2C(=O)N[C@H](C(=O)O)C(C)(C)C)C1

未命名化合物

PROCEDURE

实验过程

Compound 82 was prepared according to the procedure described for the synthesis of compound 81 by replacing formaldehyde with acetadehyde. LCMS (+ESI) m/z=421.2 [M+H]+.