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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 242648Generated: October 25, 2026

Potassium Iodide → 2-(5-{3-[2-(4-Chloro-phenylamino)-ethylamino]-propylidene}-5,11-dihydro-10-oxa-1-aza-dibenzo[a,d]cyclohepten-7-yl)-propan-2-ol

https://huagongshe.com/reaction/242648

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium IodideHCID 4875—
Reactant2,6-LutidineHCID 7937—
ReactantN-(2-Aminoethyl)-N-(4-chlorophenyl)amineHCID 12666393—
Reactant2-[5-(3-Bromo-propylidene)-5,1 1-dihydro-10-oxa-1-aza-dibenzo[a,d]cyclohepten-7-yl]-propan-2-olHCID 66685999—
SolventIsopropanolHCID 3776—
Product2-(5-{3-[2-(4-Chloro-phenylamino)-ethylamino]-propylidene}-5,11-dihydro-10-oxa-1-aza-dibenzo[a,d]cyclohepten-7-yl)-propan-2-olHCID 66758267—

Reaction Conditions

Temperature80 °C

Reaction Steps

To a solution of N-(4-chloro-phenyl)-ethane-1,2-diamine (0.68 g, 3.96 mmol) in isopropanol (8.0 mL) was added 2,6-lutidine (0.31 mL, 2.64 mmol) and catalytic potassium iodide. This mixture was heated to 80° C. and then treated with 2-[5-(3-bromo-propylidene)-5,11-dihydro-10-oxa-1-aza-dibenzo[a,d]cyclohepten-7-yl]-propan-2-ol (0.15 g, 0.4 mmol) in portions over 2 h. The solution was then stirred at 80° C. for an additional 18 h. The reaction mixture was concentrated in vacuo, then purified by flash chromatography on silica gel (gradient elution from 95% ethyl acetate/5% methanol to 90% ethyl acetate/20% methanol) to yield the title compound. 1H-NMR (DMSO) δ: 1.40 (6H, s), 2.20-2.40 (2H, m), 2.70-2.90 (3H, m), 3.10-3.30 (3H, m), 5.20 (2H, br, s), 5.80 (1H, m), 6.15 (1H, t), 6.60-6.70 (1H, m), 7.10-7.30 (4H, m) 7.50 (2H, m), 7.80 (1H, dd), 8.50 (1H, dd). ESI-MS m/z: 464 (M+1), UV retention time: 1.40 min.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08653096B2
Source datasetuspto-grants-2014_02
ORD IDord-67aec5a261344d759026b3cd0fac318d
Source noteuspto-grants-2014_02