Sodium Hydroxide → 6-Methoxy-1H-indazole-3-carboxylic acid
Reaction equation
[CH3:1][O:2][C:3]1[CH:11]=[C:10]2[C:6]([C:7]([C:12]([O:14]CC)=[O:13])=[N:8][NH:9]2)=[CH:5][CH:4]=1.[OH-].[Na+]>CO>[CH3:1][O:2][C:3]1[CH:11]=[C:10]2[C:6]([C:7]([C:12]([OH:14])=[O:13])=[N:8][NH:9]2)=[CH:5][CH:4]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To ethyl 6-methoxy-1H-indazole-3-carboxylate (0.415 mmol) in methanol (5 ml) was added 4N sodium hydroxide (aq) (8 mL, 32.0 mmol). After two hours stirring, reaction was still not finished and 6 ml of 4N NaOH was added. Upon completion of the reaction, the methanol was removed by evaporation and the water layer was washed with ethyl acetate. Subsequently the water layer was acidified and extracted with ethyl acetate twice. The latter organic layers were combined, dried (Na2SO4) and concentrated in vacuo to give 6-methoxy-1H-indazole-3-carboxylic acid (64 mg) as a brown solid.
Workup
- customreaction
- customUpon completion of the reaction
- customthe methanol was removed by evaporation
- washthe water layer was washed with ethyl acetate
- extractionextracted with ethyl acetate twice
- dry with materialdried (Na2SO4)
- concentrationconcentrated in vacuo
Sources & evidence
- ORD record
- ord-206c20e415b14e938b468fe4e4330633
- Source dataset
- uspto-grants-2014_02
- Patent number
- US08658794B2
Reaction notes
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