Thiourea → HCID 20160623, compound
Reaction equation
Cl[C:2]1[N:3]=[N:4][C:5]([C:8]2[CH:13]=[CH:12][C:11]([O:14][CH2:15][CH2:16][CH3:17])=[C:10]([O:18][CH3:19])[CH:9]=2)=[CH:6][CH:7]=1.NC(N)=[S:22]>COCCO.O>[CH3:19][O:18][C:10]1[CH:9]=[C:8]([C:5]2[CH:6]=[CH:7][C:2](=[S:22])[NH:3][N:4]=2)[CH:13]=[CH:12][C:11]=1[O:14][CH2:15][CH2:16][CH3:17]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
T13.9 g of 3-chloro-6-(3-methoxy-4-n-propoxyphenyl)pyridazine are boiled under reflux with 5.5 g of thiourea in 50 ml of ethylene glycol monomethyl ether for 8 hours. After cooling, the mixture is diluted with 250 ml of water and extracted three times with chloroform. The chloroform extracts are dried over sodium sulfate and evaporated. The residue is crystallized from ethanol/ethyl acetate. 4.8 g (34.6% of theory) of the title compound of m.p. 174°-17620 are obtained.
Workup
- temperatureAfter cooling
- extractionextracted three times with chloroform
- dry with materialThe chloroform extracts are dried over sodium sulfate
- customevaporated
- customThe residue is crystallized from ethanol/ethyl acetate
Sources & evidence
- ORD record
- ord-6abbad248c5a42f7be0c2121b9e67689
- Source dataset
- uspto-grants-1987_11
- Patent number
- US04707481
Reaction notes
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