反应详情

Representative of Scheme III is the reaction of 1-(6-methoxy-2-naphthyl)-2-methanesulfonyloxypropan-1-one with sodium borohydride in methanol to yield 1-hydroxy-1-(6-methoxy-2-naphthyl)prop-2-yl methanesulfonate. Treating that material with sodium acetate in acetic acid affords 2-(6-methoxy-2-naphthyl)propanal, which is oxidized with sodium chlorite to 2-(6-methoxy-2-naphthyl)propionic acid. By employing the optically active (S) 1-(6-methoxy-2-naphthyl)-2-methanesulfonyloxypropan-1-one there is obtained, following the same sequential steps, (S) 2-(6-methoxy-2-naphthyl)propionic acid.