HRID249590

反应详情

EQUATION

反应方程式

HRID 249590 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

3

PROCEDURE

实验过程

To a solution of 4-acetylthiomethylthio-1,2,3-triazole (6 g : 31.75 mMol.) in tetrahydrofuran (30 ml) is added dropwise at -78° C. a solution of 1M lithium bis(trimethylsilyl)amide in tetrahydrofuran (35 ml : 35 mMol.), and the mixture is stirred at the same temperature for 5 minutes and added methyl trifluoromethanesulfonate (4.0 ml : 35 mMol.). After stirring at the same temperature for 2 hours, the reaction mixture is diluted with 10% hydrochloric acid (26 ml) and water, and extracted with ethyl acetate. The extract is washed with aqueous sodium hydrogen carbonate and brine, dried over sodium sulfate, and concentrated. The residue is purified by silica gel chromatography (n-hexane : ethyl acetate=1:2) to give 4-acetylthiomethylthio-3-methyl-1,2,3-triazole 2.22 g; NMR δ (CDCl3) ppm: 2.32(s, 3H). 4.13(s, 5H). 7.77(s, 1H).IR ν (CHCl3) cm-1 : 1698, 1429, 1355, 1263, 1226, 1205, 1127, 1100, 957. mp. 37°-38° C. Yield: 34%, 4-acetylthiomethylthio-1-methyl-1,2,3- triazole [884 mg; NMR δ (CDC13) ppm: 2.35(s, 3H), 4.11(s, 3H), 4.33(s, 2H), 7.59(s, 1H).IR (CHC13) cm-1 : 1691, 1434, 1354, 1285, 1131, 1106, 1048, 1031, 956.mp. 71°-72° C. Yield: 14%], and 4-acetylthiomethylthio-2-methyl-1,2,3-triazole [175 mg; NMR δ (CDC13) ppm: 2.35 (s, 3H), 4.20(s, 3H), 4.30(s,2H), 7.56(s, 1H).IR (CHCl3) cm-1 : 1691, 1446, 1369, 1130, 1006, 990, 956.Oil. Yield: 3%].

WORKUP

后处理

  1. stirringAfter stirring at the same temperature for 2 hours
  2. extractionextracted with ethyl acetate
  3. washThe extract is washed with aqueous sodium hydrogen carbonate and brine
  4. dry with materialdried over sodium sulfate
  5. concentrationconcentrated
  6. customThe residue is purified by silica gel chromatography (n-hexane : ethyl acetate=1:2)