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HRID258602

反应详情

EQUATION

反应方程式

HRID 258602 的结构方程式

REACTANTS

反应物

3
结构：CCOC(=O)CCCCCCNS(C)(=O)=O
HCID12150839

未命名化合物

结构：CCOC(=O)CCCCCCNS(=O)(=O)CC
HCID20327654

未命名化合物

结构：CCCCCC(CCCN(CCCCCCC(=O)OCC)S(=O)(=O)CC)OC(C)=O
HCID20327717

未命名化合物

PRODUCTS

生成物

1
结构：CCCCC[C@@H](O)C#CCN(CCCCCCC(=O)O)S(C)(=O)=O
HCID22798404

未命名化合物

PROCEDURE

实验过程

The synthesis of this compound is carried out as described in Example 1 except that, in Step A, the ethyl 7-(methanesulfonamido)heptanoate is replaced by an equimolar amount of ethyl 7-ethanesulfonamidoheptanoate (Example P). The product of Step A is thus ethyl 7-[N-(4-acetoxynonyl)ethanesulfonamido]heptanoate. The subsequent step yields 7-[N-(4-hydroxynonyl)ethanesulfonamido]heptanoic acid (B).

WORKUP

后处理

  1. customThe synthesis of this compound