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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 265642Generated: October 25, 2026

Thiazole, 2-chloro-5-(2-chloroethyl)-4-methyl- → Clomethiazole

https://huagongshe.com/reaction/265642

Reaction equation

Participants

RoleNameHCIDCharge
ReactantThiazole, 2-chloro-5-(2-chloroethyl)-4-methyl-HCID 207964—
CatalystPalladiumHCID 23938—
SolventEthanolHCID 702—
ProductClomethiazoleHCID 1078391%

Reaction Steps

To a solution of 63 g (0.32 moles) of 2-chloro-4-methyl-5-(2-chloroethyl)-thiazole in 630 cm3 of a 96% ethanol 9 g of a wet palladium on charcoal catalyst (palladium content: 8%) are added. The mixture is hydrogenated at atmospheric pressure. The termination of the reaction is indicated by the cease of the hydrogen consumption. After filtering off the catalyst the solution is evaporated, the residue is dissolved in water and the solution is neutralized with sodium hydrogen carbonate (pH 7). The separated oil is shaken out with chloroform. The residue after the evaporation of the chloroform solution is distilled under reduced pressure. 47 g (91%) of 4-methyl-5-(2-chloroethyl)-thiazole are obtained. Its boiling point is 105° C. at a pressure of 0.93 KPa, nD20 =1.5430. Its active agent content is 98.8%, determined by gas chromatography.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05648498
Source datasetuspto-grants-1997_07
ORD IDord-4a5508125f1d433e834989e53f13de22
Source noteuspto-grants-1997_07