HRID273694

反应详情

EQUATION

反应方程式

HRID 273694 的结构方程式

REACTANTS

反应物

3

结构：C[C@]12CC[C@H]3[C@@H](CCC4=CC(=O)CC[C@@]43C)[C@@H]1CC[C@@H]2O

Testosterone

C19H28O2

结构：CI

Methyl iodide

CH3I

结构：CCCC[O-].[K+]

1-Butanol, potassium salt

C4H9KO

PRODUCTS

生成物

1

结构：CC1=C2CC[C@H]3[C@@H]4CC[C@H](O)[C@@]4(C)CC[C@@H]3[C@@]2(C)CCC1=O

4-Methyltestosterone

C20H30O2

PROCEDURE

实验过程

testosterone (XII) is reacted with potassium butoxide and methyl iodide to form 4-methyl-17β-hydroxyandrost-4-en-3-one