Aluminium lithium hydride → 2-(3-Methoxy-phenyl)-4-methyl-pentylamine

Participants

Reaction Steps

By working in a way similar to that described in example 17 but using LiAlH4 (0.7 g, 0.018 moles) in anhydrous ethyl ether (35 ml) and 2-(3-methoxy-phenyl)-4-methyl-pentan-nitrile (3.8 g, 0.018 moles), obtained as described in example 20, in anhydrous ethyl ether (35 ml), 3.5 g of the title compound were obtained (yield: 90.4%).

Provenance & Evidence