Cyanide → 1-Naphthalenecarbonitrile, 3,4-dihydro-6-methoxy-

Participants

Reaction Steps

The process of claim 1 wherein (1) 6-methoxytetralone is reacted with cyanide ion and a Lewis acid so as to form 6-methoxy-1-cyano-3,4-dihydronaphthalene, (2) the 6-methoxy-1-cyano3,4-dihydronaphthalene is dehydrogenated to 6-methoxy-1-cyanonaphthalene, (3) the 6-methoxy-1-cyanonaphthalene is halogenated so as to form a 6-methoxy-5-halo-1-cyanonaphthalene and then trifluoromethylated to replace the halo substituent with a trifluoromethyl group, and (4) the resultant 6-methoxy-5-trifluoromethyl-1-cyanonaphthalene is hydrolyzed to 6-methoxy-5-trifluoromethyl-1-naphthoic acid.

Provenance & Evidence