HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 28363Generated: October 30, 2026
Sodium Methoxide → 5,6-Dichloro-1-(4-hydroxy-5-hydroxymethyl-tetrahydro-furan-2-yl)-2-methoxy-1H-indole-3-carbaldehyde
https://huagongshe.com/reaction/28363
Participants
| Role | Name | HCID | Charge |
|---|
| Reactant | Sodium Methoxide | HCID 10942334 | — |
| Reactant | Chloroform methanol | HCID 21584188 | — |
| Reactant | 3-Formyl-2,5,6-trichloro-1-[3,5-di-o-(p-toluoyl)-2-deoxy-beta-d-ribofuranosyl]indole | HCID 87268761 | — |
| Solvent | Methanol | HCID 887 | — |
| Product | 5,6-Dichloro-1-(4-hydroxy-5-hydroxymethyl-tetrahydro-furan-2-yl)-2-methoxy-1H-indole-3-carbaldehyde | HCID 5272618 | 69% |
Reaction Steps
3-Formyl-2,5,6-trichloro-1-[3,5-di-O-(p-toluoyl)-2-deoxy-β-D-ribofuranosyl]indole (4.113, 198 mg, 0.33 mmol) was suspended in dry MeOH (10 mL) to which was added sodium methoxide (75 mg, 1.4 mmol). The suspension was stirred at room temperature for 16 h, after which time the solution clarified. The solvent was then removed under vacuum, and the residue was suspended in water (50 mL), and extracted with EtOAc (2×100 mL). The combined organic extracts were washed with brine (25 mL), dried over MgSO4, filtered and evaporated to yield a damp solid. The crude material was dissolved in MeOH (1 mL) and subjected to column chromatography (40×350 mm) on silica gel with 10% MeOH/CHCl3. Fractions containing product were pooled and evaporated to yield a white solid. The solid was recrystallized from warm MeOH to yield 82 mg (68%) of 4.114 as a white crystalline solid: mp 186-187° C.; Rf 0.3 (10% MeOH/CHCl3); 1H-NMR (500 MHz, DMSO-d6): δ 10.21 (s, 1H), 8.29 (s, 1H), 8.22 (s, 1H), 6.32 (dd, 1H), 5.37 (b, 1H, D2O exch.), 5.15 (b, 1H, D2O exch.), 4.43 (s, 3H), 4.41 (m, 1H), 3.83 (d, 1H), 3.68 (m, 2H), 2.53 (m, 1H), 2.11 (m, 1H). 13C-NMR (125 MHz, DMSO-d6): δ 183.22, 159.16, 129.40, 125.04, 124.73, 124.66, 121.11, 114.24, 100.02, 87.29, 82.99, 70.07, 64.16, 61.03, 38.43. HRMS (EI) m/z calcd. for C15H15Cl2NO5 359.0327, found 359.0320. Anal calcd for C15H15Cl2NO5·½H2O: C, 48.80; H, 4.37; N, 3.79. Found: C, 48.48; H, 4.61; N, 3.61.
Provenance & Evidence
| DOI | 10.6084/m9.figshare.5104873.v1 |
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| Patent number | US07419963B2 |
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| Source dataset | uspto-grants-2008_09 |
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| ORD ID | ord-2bb362aca2304c70b7f10a2d4292f26b |
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| Source note | uspto-grants-2008_09 |
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