HRID32527

反应详情

EQUATION

反应方程式

HRID 32527 的结构方程式

PROCEDURE

实验过程

The title compound was prepared in 75% yield according to a procedure similar to the one described for intermediate 17 above but starting from 6-[1-(3,4-dimethoxybenzyl)-4-phenyl-1H-imidazol-5-yl]-4-(methylthio)thieno[2,3-d]pyrimidine (example 9) in place of 6-(1-methyl-4-phenyl-1H-imidazol-5-yl)-4-(methylthio)thieno[2,3-d]pyrimidine (example 7);