HRID32575

反应详情

EQUATION

反应方程式

HRID 32575 的结构方程式

PROCEDURE

实验过程

The title compound was prepared by a similar process to that described for Intermediate 17 but using 6-[4-(4-iodophenyl)-1-methyl-1H-imidazol-5-yl]-4-(methylthio)thieno[2,3-d]pyrimidine (Intermediate 62) in place of 6-(1-methyl-4-phenyl-1H-imidazol-5-yl)-4-(methylthio)thieno[2,3-d]pyrimidine (example 7). Solid (200 mg, 100%);