HRID32581

反应详情

EQUATION

反应方程式

HRID 32581 的结构方程式

PROCEDURE

实验过程

The title compound was prepared by a similar process to that described for Example 8 but using 6-[4-(4-Bromophenyl)-1-methyl-1H-imidazol-5-yl]-4-(methylsulfonyl)thieno[2,3-d]pyrimidine (Intermediate 68) in place of 6-(1-Methyl-4-phenyl-1H-imidazol-5-yl)-4-(methylsulfonyl)thieno[2,3-d]pyrimidine (intermediate 17); Solid (568 mg, 95%);