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HRID339265

反应详情

EQUATION

反应方程式

HRID 339265 的结构方程式

REACTANTS

反应物

2
结构：C[C@@H](C(=O)N[C@H](C(=O)N1Cc2cc(C(=O)O)ccc2C[C@H]1C(=O)N[C@@H]1CCCc2ccccc21)C(C)(C)C)N(C)C(=O)OC(C)(C)C
HCID86705870

未命名化合物

结构：COC(=O)[C@H](Cc1ccccc1)NC(=O)[C@@H]1Cc2ccc([C@H]3C[C@@H](C(=O)N[C@@H]4CCCc5ccccc54)N(C(=O)[C@@H](NC(=O)[C@H](C)N(C)C(=O)OC(C)(C)C)C(C)(C)C)C3)cc2CN1C(=O)[C@@H](NC(=O)[C@H](C)N(C)C(=O)OC(C)(C)C)C(C)(C)C
HCID86705907

未命名化合物

PRODUCTS

生成物

1
结构：C[C@@H](C(=O)N[C@H](C(=O)N1Cc2cc([C@H]3C[C@@H](C(=O)N[C@@H]4CCCc5ccccc54)N(C(=O)[C@@H](NC(=O)[C@H](C)N(C)C(=O)OC(C)(C)C)C(C)(C)C)C3)ccc2C[C@H]1C(=O)N[C@@H](Cc1ccccc1)C(=O)O)C(C)(C)C)N(C)C(=O)OC(C)(C)C
HCID86705906

未命名化合物

收率 60%

PROCEDURE

实验过程

Following a procedure analogous to that for the synthesis of Compound K of Example 1, (S)-methyl 2-((S)-2-((S)-2-((S)-2-((tert-butoxycarbonyl)(methyl)amino)propanamido)-3,3-dimethylbutanoyl)-7-((3R,5S)-1-((S)-2-((S)-2-((tert-butoxycarbonyl)(methyl)amino)propanamido)-3,3-dimethylbutanoyl)-5-(((R)-1,2,3,4-tetrahydronaphthalen-1-yl)carbamoyl)pyrrolidin-3-yl)-1,2,3,4-tetrahydroisoquinoline-3-carboxamido)-3-phenylpropanoate (290 mg, 0.25 mmol) was converted to the title compound (172 mg, 60%). MS (ESI+) m/z 1163.9 (M+H)+.