Fumaric Acid → Fumaric acid molybdenum
Reaction equation
[C:1]([OH:8])(=[O:7])/[CH:2]=[CH:3]/[C:4]([OH:6])=[O:5].C([O-])(=O)C.[Mo+4:13].C([O-])(=O)C.C([O-])(=O)C.C([O-])(=O)C>CO>[Mo:13].[C:1]([OH:8])(=[O:7])/[CH:2]=[CH:3]/[C:4]([OH:6])=[O:5]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
0.597 g (5.14 mmol) of fumaric acid and 1,000 g (2.34 mmol) of molybdenum acetate were dissolved in 900 ml of methanol. After this was stirred for three days at the room temperature, this was kept still for a few days. Thereafter, its precipitation product was suction-filtered, rinsed sufficiently with methanol and then vacuum-dried for 60° C./4 hours, whereby 0.970 g of target substance was obtained. This substance had the specific surface area of 469 m2 /g. And, a measurement according to the HK method using argon revealed that the substance had the pore diameter of 5.8 Å.
Workup
- waitthis was kept still for a few days
- customThereafter, its precipitation product
- filtrationwas suction-filtered
- washrinsed sufficiently with methanol
- customvacuum-dried for 60° C./4 hours, whereby 0.970 g of target substance
- customwas obtained
Sources & evidence
- ORD record
- ord-16e899be161344d6ac639b79393768ec
- Source dataset
- uspto-grants-1999_01
- Patent number
- US05862796
Reaction notes
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