1,4-Dioxane → 1-(3-Methoxy-4-nitrophenyl)-3-pyrrolidinol
Reaction equation
F[C:2]1[CH:7]=[CH:6][C:5]([N+:8]([O-:10])=[O:9])=[C:4]([O:11][CH3:12])[CH:3]=1.O1CCOCC1.[NH:19]1[CH2:23][CH2:22][C@@H:21]([OH:24])[CH2:20]1>O>[CH3:12][O:11][C:4]1[CH:3]=[C:2]([N:19]2[CH2:23][CH2:22][CH:21]([OH:24])[CH2:20]2)[CH:7]=[CH:6][C:5]=1[N+:8]([O-:10])=[O:9]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
8 g (46 mmol) of 4-fluoro-2-methoxy-1-nitrobenzene 1,80 ml of dioxane and 8.14 g (0.095 mol) of (R)-(+)-3-pyrrolidinol are respectively placed in the reactor. The mixture is refluxed for one hour. The reaction medium is poured into a mixture of water (100 ml)-ice (200 g). A yellow product precipitates. This product is filtered off, washed with water (3×30 ml) and then dried under vacuum at 45° C. 8.38 g (75%) of 1-(3-methoxy-4-nitrophenyl)pyrrolidin-3-ol (2) are thus recovered.
Workup
- temperatureThe mixture is refluxed for one hour
- customA yellow product precipitates
- filtrationThis product is filtered off
- washwashed with water (3×30 ml)
- customdried under vacuum at 45° C
- custom8.38 g (75%) of 1-(3-methoxy-4-nitrophenyl)pyrrolidin-3-ol (2) are thus recovered
Sources & evidence
- ORD record
- ord-436ebbd6ad364fab9724a6034d221130
- Source dataset
- uspto-grants-2007_02
- Patent number
- US07179301B2
Reaction notes
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