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HRID35242

反应详情

EQUATION

反应方程式

HRID 35242 的结构方程式

REACTANTS

反应物

2
结构：COc1cc2c(cc1OC)CNCC2
HCID15623

Heliamine

C11H15NO2

结构：CC(=O)Oc1ccc(CC(=O)Cl)cc1
HCID182488

4-(2-Chloro-2-oxoethyl)phenyl acetate

C10H9ClO3

PRODUCTS

生成物

1
结构：COc1cc2c(cc1OC)CN(C(=O)Cc1ccc(OC(C)=O)cc1)CC2
HCID21295827

未命名化合物

PROCEDURE

实验过程

Using the procedure described in Example 12, 15.0 g of 1,2,3,4-tetrahydro-6,7-dimethoxyisoquinoline was reacted with 4-acetoxyphenylacetyl chloride to give 13.0 g of N-(4-acetoxyphenylacetyl)-1,2,3,4-tetrahydro-6,7-dimethoxyisoquinoline.