Hydrochloric Acid → 2-Biphenylol, 5-nitro-

Participants

Reaction Conditions

Reaction Steps

5.3 g (0.02 mole) of 2-bromo-1-methoxymethoxy-4-nitrobenzene from step B and 2.80 g (0.023 mole) of phenylboric acid were dissolved in 70 mL of 1,2-dimethoxyethane under argon. Then, 0.5 g (0.0005 mole) of tetrakis-(triphenylphosphine)palladium and 13 mL of 2 N potassium carbonate solution were added, and the reaction mixture was heated to 80° C. At the end of the reaction, the reaction mixture was poured into 100 mL of ethyl acetate and the organic phase was extracted with dilute sodium hydroxide solution and then dried with magnesium sulfate. The solvent was distilled off in a rotary evaporator, and the residue was purified on silica gel using petroleum ether/ethyl acetate (9:1). The product thus obtained was heated to 50° C. in a mixture of 40 mL of ethanol and 15 mL of a 2.9 M ethanolic hydrochloric acid solution. After neutralization with NaOH, the solvent was distilled off in a rotary evaporator, and the residue was purified by vacuum distillation. This gave 3.5 g (82% of the theoretical) of 2-hydroxy-5-nitrobiphenyl.

Provenance & Evidence