Sodium Hydroxide → 5-cyclopropyl-1-(2-chloro-4-methanesulfonylphenyl)-1H-pyrazole-4-carboxylic acid

Participants

Reaction Steps

5-Cyclopropyl-1-(2-chloro-4-methanesulfonylphenyl)-1H-pyrazole-4-carboxylic acid methyl ester is hydrolyzed with a base such as sodium hydroxide in water to form 5-cyclopropyl-1-(2-chloro-4-methanesulfonylphenyl)-1H-pyrazole-4-carboxylic acid, analogous to the formula IX′ acid. The carboxylic acid pyrazole is then activated with coupling agent such as thionyl chloride to form the activated compound, analogous to the formula X′ compound. The activated compound is then coupled with guanidine to form the NHE-1 inhibitor, N-{5-cyclopropyl-1-(2-chloro-4-methanesulfonylphenyl)-1H-pyrazole-4-carbonyl}-guanidine.

Provenance & Evidence