HRID35393

反应详情

EQUATION

反应方程式

HRID 35393 的结构方程式

PROCEDURE

实验过程

The procedure of Example 26 was repeated except that in place of the fluoroxytrifluoromethane, there was added bis-(fluoroxy)difluoromethane at a rate of 2.40 parts per hour for one hour. Analysis of the reaction product by liquid chromatographic techniques indicated 38% N-(2-fluorophenyl)methanesulfonamide, 12% N-(4-fluorophenyl)methanesulfonamide, 10% N-(2,4-difluorophenyl)methanesulfonamide and 1% N-(2,6-difluorophenyl)methanesulfonamide at 97% conversion.