Imidazole → HCID 22866033, compound

Participants

Reaction Steps

D-glutamic acid (1) was treated with sodium nitrite in hydrochloric acid to produce (R)-1,4-butyrolactone-4-carboxylic acid (2). Compound 2 was then reduced by borane-dimethyl sulfide complex in THF to give the corresponding (R)-4-(hydroxymethyl)-4-butyrolactone (4), which was subsequently treated with tert-butyldiphenylsilyl chloride in methylene chloride using imidazole as a catalyst to afford (R)-5-O-tert-butyldiphenylsilyl-4-hydroxymethyl-1,4-butyrolactone (53). The protected lactone 53 was opened with sodium hydroxide in ethanol and then converted to the methyl ester of 5-[(tert-butyldiphenylsilyl)oxy]-4-(R)-hydroxypentanoic acid (54) by reaction with dimethyl sulfate in dimethyl sulfoxide. Commpound 54 was transformed into the methyl ester of 5-[(tert-butyldiphenylsilyl)oxy]-4-(S)-iodopentanoic acid (55) by treatment with triphenylphosphine, imidazole and iodine. Displacement of the iodo group in compound 55 by thioacetate in toluene occurred readily to give the methyl ester of 4-(R)-(acetylthio)-5-[(tert-butyldiphenylsilyl)oxy]pentanoic acid (56). Compound 56 was then treated with 2 equivalents of diisobutylaluminum hydride (DIBAL) in toluene to reductively deprotect the sulfur and reduce the methyl ester to an aldehyde, thereby producing the thiolactol via spontaneous cyclization. The thiolactol was acetylated with acetic anhydride in pyridine to give 1-o-acetyl-5-o-(tert-butyldiphenylsilyl)-2,3-dideoxy-4-thio-L-ribofuranose (57): 1HNMR (CDCl3) delta 7.67 (m, 4H, ArH), 7.40 (m, 6H, ArH), 6.10 (m, 1H, 1-H), 3.70 (m, 1H, 4-H), 3.52 (m, 2H, 5-H), 2.20 (m, 2H, CH2), 2.00 (2 s, 3H, CH3CO--), 1.92 (m, 2H, CH2), 1.08 (s, 9H, tert-butyl).

Provenance & Evidence