4-Fluorobenzonitrile → HCID 21840714, compound

HRID 356234Notes

Reaction equation

HRID 356234 reaction equation
F[C:2]1[CH:9]=[CH:8][C:5]([C:6]#[N:7])=[CH:4][CH:3]=1.[OH:10][C:11]1([CH:18]=[CH:17][CH:16]=[C:15]([F:19])[CH:14]1[OH:20])C#N>>[C:6]([C:5]1[CH:8]=[CH:9][C:2]([O:10][C:11]2[CH:18]=[CH:17][CH:16]=[C:15]([F:19])[C:14]=2[O:20][C:2]2[CH:9]=[CH:8][C:5]([C:6]#[N:7])=[CH:4][CH:3]=2)=[CH:3][CH:4]=1)#[N:7]

Participants

3

Reactant 2

HCID 145174-FluorobenzonitrileHCID 21840715HCID 21840715, compound

Product 1

HCID 21840714HCID 21840714, compoundYield 89.4%

Procedure

The compound 1,2-bis-(4-cyanophenoxy)-3-fluoro-benzene was prepared according to the procedure described in Example 1 by reacting 4-fluorobenzonitrile with 1,2-dihydroxy-3-fluorobenzonitrile. The product was recrystallized from ethanol/water (4:1). The yield was 89.4% of the title compound with the formula: ##STR8##

Workup

  1. customThe compound 1,2-bis-(4-cyanophenoxy)-3-fluoro-benzene was prepared
  2. customThe product was recrystallized from ethanol/water (4:1)

Sources & evidence

ORD record
ord-68815f3ed2c84ba18fa356e86f3ceafb
Source dataset
uspto-grants-1998_11
Patent number
US05834620

Reaction notes

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