Methyl bromoacetate → HCID 20065999, compound
Reaction equation
[CH2:1]([NH:8][CH2:9][CH2:10][C:11]1[CH:16]=[CH:15][C:14]([OH:17])=[CH:13][CH:12]=1)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.CC(C)([O-])C.[K+].Br[CH2:25][C:26]([O:28][CH3:29])=[O:27]>C(COC)OC.CCOCC>[CH2:1]([NH:8][CH2:9][CH2:10][C:11]1[CH:12]=[CH:13][C:14]([O:17][CH2:25][C:26]([O:28][CH3:29])=[O:27])=[CH:15][CH:16]=1)[C:2]1[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=1Participants
Procedure
The starting material was obtained as follows: N-Benzyltyramine (9.08 g) was added to a stirred solution of potassium t-butoxide (4.5 g) in dimethoxyethane (80 ml). To the clear solution was added methyl bromoacetate (6.2 g) and the mixture was stirred overnight. The mixture was diluted with ether (250 ml) and washed with water (2×25 ml). The ethereal solution was dried (MgSO4) and evaporated, to give methyl 4-[2-(benzylamino)ethyl]phenoxyacetate (15.0 g) as an oil, which was dissolved in isopropanol and teated with phenylglycidyl ether (7.5 g). The solution was heated to reflux for 1 hour, and then evaporated. The residue was dissolved in toluene and volatile material evaporated before being purified by chromatography on K60 silica (220 g) using 1% methanol in dichloromethane. Methyl 4-[2-(N-benzyl-N-(2-hydroxy-3-phenoxypropyl)amino)ethyl]phenoxyacetate was obtained as an oil (9.5 g), NMR: 2.55-2.85[m,6H, CH2NHCH2CH2 ]; 3.65-4.05[m,8H, PhOCH2CHOH and PhCH2 and OCH3 ]; 4.67]s, 2H, OCH2CO]; 6.73-7.40[m, 14H, aromatic H].
Workup
- customThe starting material was obtained
- washwashed with water (2×25 ml)
- dry with materialThe ethereal solution was dried (MgSO4)
- customevaporated
Sources & evidence
- ORD record
- ord-b56276eab8d549d59758277cb6de6b74
- Source dataset
- uspto-grants-1991_03
- Patent number
- US04999377
Reaction notes
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