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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 366694Generated: October 31, 2026

4-Pentyn-2-ol, (2R)- → HCID 178433231, compound

https://huagongshe.com/reaction/366694

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-Pentyn-2-ol, (2R)-HCID 7014874—
ReactantHCID 178433242HCID 178433242—
CatalystHCID 178418397HCID 178418397—
SolventDimethylformamideHCID 6228—
SolventTriethylamineHCID 8471—
ProductHCID 178433231HCID 178433231—

Reaction Steps

Using Method C above, (R)-pent-4-yn-2-ol (68 mg, 0.82 mmol) (see Example 78 below) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(4-methyl-1H-imidazol-5-yl)methylene]-2H-indol-2-one (100 mg, 0.27 mmol) (Starting Material 3 supra) using (Ph3P)4Pd (31 mg, 0.03 mmol) and Cul (6 mg) in a mixture of DMF (5 mL) and Et3N (5 mL) as solvent at 80° C. for 4 hrs. Upon completion, the reaction mixture was concentrated and the residue was chromatographed on a silica gel column with neat CH3CN then THF and finally MeOH as elution solvent. The resulting (R)-(Z)-1,3-Dihydro-5-fluoro-4-(4-hydroxy-1-pentynyl)-3-[(4-methyl-1H-imidazol-5-yl)methylene]-2H-indol-2-one was triturated with Et2O and then recrystalized from superheated EtOH. (Yield 18 mg, 20%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06130239
Source datasetuspto-grants-2000_10
ORD IDord-6a4dea18d2794e719f6814f703e2ddcc
Source noteuspto-grants-2000_10