HRID366702

反应详情

EQUATION

反应方程式

HRID 366702 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

3

PROCEDURE

实验过程

Using Method C above, 4-pentynoic acid methyl ester (75.7 mg, 0.68 5 mmol) (see Example 8, supra) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one (100 mg, 0.26 mmol) (Starting Material 6, supra) using (Ph3P)4Pd (31.2 mg) and Cul (5.0 mg) as catalyst in DMF (4 mL) and Et3N (4 mL) as solvent at 80° C. for 7 h to yield (Z)-5-[2,3-Dihydro-5-fluoro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-4-pentynoic acid methyl ester. (Yield 86 mg, 90%).