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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 367122Generated: October 29, 2026

Benzyl Bromide → HCID 15485503, compound

https://huagongshe.com/reaction/367122

Reaction equation

Participants

RoleNameHCIDCharge
ReactantBenzyl BromideHCID 7498—
ReactantLithium hydrideHCID 62714—
Reactant4H-Pyrido[3,2-e]-1,3-thiazin-4-one, 2-[(4-bromophenyl)amino]-HCID 5230603—
ProductHCID 15485503HCID 1548550365.4%

Reaction Steps

The reaction procedure of Example 11 was followed except that 900 mg (2.69 mmol) of 2-(4-bromoanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 24 mg of lithium hydride and 507 mg of benzyl bromide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 746 mg of 3-benzyl-2-[(4-bromophenyl)imino]-2,3-dihydro-4H-pyrido[3,2-e]-1,3-thiazin-4-one (recrystallized from a mixture of ether and hexane) as a low polarity substance and 163 mg of 2-[N-benzyl-N-(4-bromophenyl)amino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (recrystallized from a mixture of ether and ethanol) as a high polarity substance.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06133258
Source datasetuspto-grants-2000_10
ORD IDord-f4994573036346d9854530f430cb0218
Source noteuspto-grants-2000_10