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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 367123Generated: October 25, 2026

Iodoethane → 2-[(4-chlorophenyl)imino]-2,3-dihydro-3-ethyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one

https://huagongshe.com/reaction/367123

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantLithium hydrideHCID 62714—
Reactant4H-Pyrido[3,2-e]-1,3-thiazin-4-one, 2-[(4-chlorophenyl)amino]-HCID 4292070—
Product2-[(4-chlorophenyl)imino]-2,3-dihydro-3-ethyl-4H-pyrido[3,2-e]-1,3-thiazin-4-oneHCID 2328756858.4%

Reaction Steps

The reaction procedure of Example 11 was followed except that 900 mg (3.11 mmol) of 2-(4-chloroanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 25 mg of lithium hydride and 584 mg of ethyl iodide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 577 mg of 2-[(4-chlorophenyl)imino]-2,3-dihydro-3-ethyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one (58%, recrystallized from a mixture of ether and hexane) as a low polarity substance and 61 mg of 2-[N-(4-chlorophenyl)-N-ethylamino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (6%, recrystallized from ether) as a high polarity substance.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06133258
Source datasetuspto-grants-2000_10
ORD IDord-6a11ca485d61461a93f3976ec20316ef
Source noteuspto-grants-2000_10