1-Iodopropane → HCID 23287702, compound

Participants

Reaction Steps

The reaction procedure of Example 11 was followed except that 900 mg (2.36 mmol) of 2-(4-iodoanilino)-4H-pyrido(3,2-e]-1,3-thiazin-4-one, 23 mg of lithium hydride and 482 mg of propyl iodide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 653 mg of 2-[(4-iodophenyl)imino]-2,3-dihydro-3-propyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one (65%, recrystallized from a mixture of ether and hexane) as a low polarity substance and 40 mg of 2-[N-(4-iodophenyl)-N-propylamino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (4%, recrystallized from ether) as a high polarity substance.

Provenance & Evidence