Methyl iodide → HCID 23287719, compound

Participants

Reaction Steps

The reaction procedure of Example 11 was followed except that 900 mg (2.36 mmol) of 2-(4-iodoanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 23 mg of lithium hydride and 402 mg of methyl iodide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 580 mg of 2-[(4-iodophenyl)imino]-2,3-dihydro-3-methyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one (62%, recrystallized from a mixture of ether and hexane).

Provenance & Evidence