Diisopropylamine → 2-Carbomethoxy-2-(t-butyl)thiomethyl-indan

Participants

Reaction Conditions

Reaction Steps

Dissolve diisopropylamine (1.90 mL, 7.8 mmol) in anhydrous tetrahydrofuran (8 mL), cool to -20° C. and place under an argon atmosphere. Add, by dropwise addition, n-butyllithium (3.12 mL of a 2.5N solution in hexanes, 7.8 mmol) and stir for 20 minuses while cooling to -70° C. Add, by dropwise addition, a solution of 2-carbomethoxy-indan (1.34 g, 7.8 mmol) in anhydrous tetrahydrofuran (8 mL). Stir at -70° C. for an additional 30 minutes then add trimethylsilyl chloride (freshly distilled from barium oxide, 1.0 mL, 7.8 mmol). Allow to warm to 10° C., evaporate the solvent in vacuo and dry the residue under vacuum for 30 minutes. Suspend the residue in methylene chloride (30 mL), add zinc bromide (300 mg, 1.3 mmol) followed by t-butyl chloromethylsulfide (1.08 g, 7.8 mmol). Stir for 15 minutes as room temperature and add additional zinc bromide (500 mg, 2.2 mmol). Pour onto excess saturated sodium hydrogen carbonate and shake vigorously. Separate the organic phase and extract the aqueous phase with methylene chloride (30 mL). Combine the organic phases, cry (MgSO4) and evaporate the solvent in vacuo to give crude product as a brown oil (2.12 g, 98%). Purify by silica gel chromatography (30°-70° C. methylene chloride/hexane) and recrystallize (methanol) to give 2-carbomethoxy-2-(t-butyl)thiomethylindan as a crystalline solid (1.3 g, 61%).

Provenance & Evidence