Sodium hydride → Methyl 2-[2-(3-phenyl-1,2,4-thiadiazol-5-yloxy)-phenyl]-3-fluoromethoxy-acrylate
Reaction equation
[C:1]1([C:7]2[N:11]=[C:10](S(C)(=O)=O)[S:9][N:8]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[OH:16][C:17]1[CH:22]=[CH:21][CH:20]=[CH:19][C:18]=1[C:23](=[CH:28][O:29][CH2:30][F:31])[C:24]([O:26][CH3:27])=[O:25].[H-].[Na+]>CN(C)C=O>[C:1]1([C:7]2[N:11]=[C:10]([O:16][C:17]3[CH:22]=[CH:21][CH:20]=[CH:19][C:18]=3[C:23](=[CH:28][O:29][CH2:30][F:31])[C:24]([O:26][CH3:27])=[O:25])[S:9][N:8]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1Participants
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A solution of 3.2 g (0.005 mol) of 3-phenyl-5-methanesulphonyl-1,2,4-thiadiazole and 2.3 g of methyl 2-(2-hydroxyphenyl)-3-fluoromethoxy-acrylate in 10 ml of dry dimethylformamide is treated at 0° C. with 0.2 g (0.005 mol) of 80% strength sodium hydride in mineral oil. The mixture is stirred for 4 hours at this temperature, and for a further 18 hours without cooling, and then concentrated. The residue is taken up using ethyl acetate, the solution is washed with water, and the organic phase is dried over sodium sulphate and concentrated again. The crude product is chromatographed on silica gel using hexane/acetone (7:3). 1.3 g (67% of theory) of methyl 2-[2-(3-phenyl-1,2,4-thiadiazol-5-yloxy)-phenyl]-3-fluoromethoxy-acrylate are obtained as a yellow, highly viscous oil.
Workup
- temperaturefor a further 18 hours without cooling
- concentrationconcentrated
- washthe solution is washed with water
- dry with materialthe organic phase is dried over sodium sulphate
- concentrationconcentrated again
- customThe crude product is chromatographed on silica gel
Sources & evidence
- ORD record
- ord-9ab998fbbdc74915949725c742fe2a97
- Source dataset
- uspto-grants-2000_02
- Patent number
- US06031107
Reaction notes
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