Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 380825Generated: October 27, 2026

1-Pentyn-3-ol → rac-(Z)-1,3-dihydro-4-(3-hydroxy-1-pentynyl)-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one

https://huagongshe.com/reaction/380825

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1-Pentyn-3-olHCID 92981—
Reactant(Z)-1,3-dihydro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-oneHCID 15548053—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
CatalystHCID 178418476HCID 178418476—
SolventDimethylformamideHCID 6228—
SolventTriethylamineHCID 8471—
Productrac-(Z)-1,3-dihydro-4-(3-hydroxy-1-pentynyl)-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-oneHCID 9883624—

Reaction Steps

Using Method C above, 1-pentyn-3-ol (40 mg, 0.48 mmol) (Aldrich) was coupled with (Z)-1,3-dihydro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one (146 mg, 0.4 mmol) (Starting Material 2 supra) using (Ph3P)2PdCl2 (20 mg) and CuI (10 mg) as catalyst in DMF (2 mL) and Et3N (2 mL) as solvent at 70° C. for 15 h to yield rac-(Z)-1,3-dihydro-4-(3-hydroxy-1-pentynyl)-3-[(3methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 78 mg, 60%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06303793B1
Source datasetuspto-grants-2001_10
ORD IDord-00804425b74d4a3da6d0a2b6595cf731
Source noteuspto-grants-2001_10