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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 380860Generated: October 26, 2026

1-Pentyn-3-ol → rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one

https://huagongshe.com/reaction/380860

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1-Pentyn-3-olHCID 92981—
Reactant(3Z)-5-fluoro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylidene]-2,3-dihydro-1H-indol-2-oneHCID 18363902—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
CatalystHCID 178418397HCID 178418397—
SolventDimethylformamideHCID 6228—
SolventTriethylamineHCID 8471—
Productrac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-oneHCID 59959878—

Reaction Steps

Using Method C above, 1-pentyn-3-ol (54.5 mg, 0.65 mmol) (Aldrich) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one (100 mg, 0.26 mmol) (Starting Material 6, supra) using (Ph3P)4Pd (30 mg) and CuI (5 mg) as catalyst in DMF (5 mL) and Et3N (5 mL) as solvent at 85° C. for 18 h to yield rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 56 mg, 64%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06303793B1
Source datasetuspto-grants-2001_10
ORD IDord-400d4baac0594fe9b556377579345612
Source noteuspto-grants-2001_10