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HRID395775

反应详情

EQUATION

反应方程式

HRID 395775 的结构方程式

REACTANTS

反应物

2
结构：COc1ccc(C(=O)O)cc1[N+](=O)[O-]
HCID66640

Benzoic acid, 4-methoxy-3-nitro-

C8H7NO5

结构：CC(C)(C)c1ccc(C(=O)Nc2ccccc2N)cc1
HCID1133079

N-(2-aminophenyl)-4-tert-butylbenzamide

C17H20N2O

PRODUCTS

生成物

1
结构：COc1ccc(C(=O)Nc2ccccc2NC(=O)c2ccc(C(C)(C)C)cc2)cc1[N+](=O)[O-]
HCID31973964

未命名化合物

收率 84%

PROCEDURE

实验过程

Using the procedure described in Example 102, Part A, 3-nitro-4-methoxybenzoic acid (2.8 mmol) and N1-(4-tert-butylbenzoyl)-1,2-benzenediamine (1.9 mmol) yielded 0.70 mg (84%) of the title compound.