Water → 6-azidohexanoic Acid
Reaction equation
[N:1]([CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][C:9]([O:11]CC)=[O:10])=[N+:2]=[N-:3].[OH-].[K+].O>CO>[N:1]([CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][C:9]([OH:11])=[O:10])=[N+:2]=[N-:3]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 0 °C
Procedure
Ethyl 6-azidohexanoate (8.59 g, 44.8 mmol) and KOH (13.0 g, 0.231 mol) were dissolved into a mixture of 120 ml of water and 180 ml of MeOH. The solution was stirred at 0° C. for 2 hrs then MeOH was removed in vacuo. The aqueous layer was extracted by CHCl3 (2×100 ml), acidified to pH=l by 2N aqueous HCl and extracted by Et2O (2×100 ml). The organic layers were combined, washed with water (100 ml) and dried over Na2SO4. After filtration and evaporation of solvent, 6-azidohexanoic acid (6.56 g, 93%) was obtained as a colorless oil.
Workup
- customMeOH was removed in vacuo
- extractionThe aqueous layer was extracted by CHCl3 (2×100 ml)
- extractionextracted by Et2O (2×100 ml)
- washwashed with water (100 ml)
- dry with materialdried over Na2SO4
- filtrationAfter filtration and evaporation of solvent
Sources & evidence
- ORD record
- ord-873b79d430894343912557ad92959b6c
- Source dataset
- uspto-grants-2003_08
- Patent number
- US06608086B2
Reaction notes
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