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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 399449Generated: October 25, 2026

Sodium Iodide → 8-(4-Methylpiperazin-1-yl)naphthalen-2-ol

https://huagongshe.com/reaction/399449

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantNitrogen mustard hydrochlorideHCID 5935—
Reactant1-NaphtholHCID 7005—
Reactant8-Amino-2-naphthalenolHCID 8358—
ReactantAmmonium HydroxideHCID 14923—
ReactantSodium BicarbonateHCID 516892—
SolventMethanolHCID 887—
SolventAcetonitrileHCID 6342—
SolventDichloromethaneHCID 6344—
Product8-(4-Methylpiperazin-1-yl)naphthalen-2-olHCID 10800217—

Reaction Steps

To a stirring solution of 8-amino-2-naphthol (3.28 g, 20 mmol, Aldrich Chem. Co.) in 100 mL of acetonitrile was added sodium bicarbonate (7.42 g, 88 mmol), sodium iodide (6.72 g, 44 mmol) and mechlorethamine hydrochloride (4.32 g, 22 mmol). Under nitrogen, the reaction was heated to reflux and stirred for another 2 hr. The reaction mixture was then allowed to cool to room temperature and was stirred overnight. A thin layer chromatography (tlc) using methylene chloride: methanol: conc. ammonium hydroxide (90:10:1) showed the more polar product (Rf 0.25) with only a trace of the starting naphthol. Silica gel (4.5 g) was added and the reaction mixture was concentrated in vacuo to a dry purple solid. This was added to a column of silica gel (ca. 400 g) and eluted with 2 L volumes of CH2Cl2, CH2Cl2 :CH3OH (40:1), CH2Cl2 :CH3OH:conc. NH4OH (20:1:0.1) and finally 4 L of CH2Cl2 :CH3OH:conc. NH4CH (10:1:0.1). The appropriate fractions were combined to yield a purple-black solid, 5.26 g, mp 184°-185° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05821245
Source datasetuspto-grants-1998_10
ORD IDord-347a497a622b47bc996cee0da2273737
Source noteuspto-grants-1998_10