Hydrochloric Acid → (S)-2-(5-(4-(3-(4-Fluorophenyl)ureido)phenyl)-1-oxoisoindolin-2-yl)-3-methylbutanoic acid

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Reaction Steps

The compound of example 224 (0.500 g, 0.00102 mol) was taken in THF (8 mL) and MeOH (1 mL) and to this reaction mixture, 1 N LiOH (0.213 g, 0.0051 mol) was added and stirred at room temperature for 2-3 h. After completion of the reaction, solvent was evaporated and the residue obtained was dissolved in water and acidified with 1 N HCl to obtain the title compound, which was filtered and dried.

Provenance & Evidence