Hydrochloric Acid → (S)-2-(5-(4-(3-(2-Fluorophenyl)thioureido)phenyl)-1-oxoisoindolin-2-yl)-3-methylbutanoic acid

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Reaction Steps

The compound of example 256 (0.224 g, 0.000456 mol) was taken in THF (4 mL) and MeOH (1 mL) and to this reaction mixture, 1 N LiOH (0.095 g, 0.0022 mol) was added and stirred at room temperature for 2-3 h. After completion of the reaction, the solvent was evaporated and the residue obtained was dissolved in water and acidified with 1 N HCl to obtain the title compound, which was filtered and dried.

Provenance & Evidence