HRID407550

反应详情

EQUATION

反应方程式

HRID 407550 的结构方程式

PROCEDURE

实验过程

The title compound was prepared from 8-ethyl-4-hydroxy-2-(4-isopropylthiazole-2-yl)-7-methoxyquinoline (69) and intermediate 43 following the procedure (Steps D-F) reported for the preparation of 17-[2-(4-isopropylthiazole-2-yl)-7-methoxy-8-methyl-quinolin-4-yloxy]-13-methyl-2,14-dioxo-3,13-diazatricyclo[13.3.0.04,6]octadec-7-ene-4-carboxylic acid (46): m/z=661 (M+H)+.