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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 407611Generated: October 25, 2026

Potassium Acetate → 2-Bromo-6-(6-tert-butyl-8-fluoro-1-oxophthalazin-2(1H)-yl)-4-fluorobenzaldehyde

https://huagongshe.com/reaction/407611

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium AcetateHCID 517044—
Reactant4,7-Dimethoxy-1,10-phenanthrolineHCID 10462298—
Reactant2,6-Dibromo-4-fluorobenzaldehydeHCID 44474666—
Reactant6-(tert-Butyl)-8-fluorophthalazin-1(2H)-oneHCID 59473765—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
Solvent1,4-DioxaneHCID 31275—
Product2-Bromo-6-(6-tert-butyl-8-fluoro-1-oxophthalazin-2(1H)-yl)-4-fluorobenzaldehydeHCID 8668391130%

Reaction Steps

To a solution of 102a (767 mg, 2.72 mmol), 6-tert-butyl-8-fluorophthalazin-1(2H)-one 101h (300 mg, 1.36 mmol) in dioxane (50 mL) was added KOAc (267 mg, 2.72 mmol), CuI (259 mg, 1.36 mmol), and 4,7-dimethoxy-1,10-phenanthroline (327 mg, 1.36 mmol). After bubbling nitrogen through the resulting solution for 30 min, the mixture was stirred at 90 degree for 10 h. It was allowed to cool down to room temperature and H2O (100 mL) was added. The aqueous layer was separated and extracted with ethyl acetate (2×200 mL). The combined organic layers was washed with brine (100 mL) and dried over sodium sulfate. The drying agent was removed by filtration and the filtrate was concentrated under reduced pressure. The residue was purified on flash column eluting with PE/EA (15:1) to afford 102b (172 mg, 30%). LCMS: [M+H]+ 421. 1H NMR (500 MHz, CDCl3) δ 10.20 (s, 1H), 8.20 (s, 1H), 7.49-7.51 (m, 3H), 7.25 (m, 1H), 1.36 (s, 9H).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08754077B2
Source datasetuspto-grants-2014_06
ORD IDord-a96a7249d9484a8d9fa873d6a3533910
Source noteuspto-grants-2014_06