HRID417737

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID13821101

未命名化合物

结构：COC(=O)NC(C(=O)N1CC2(CC2)CC1c1ncc(-c2ccc(-c3ccc4cc(-c5cnc(C6C7CCC(C7)N6C(=O)C(NC(=O)OC)C6CC6)[nH]5)ccc4c3)cc2)[nH]1)C(C)C

HCID66620456

未命名化合物

PRODUCTS

生成物

结构：COC(=O)NC(C(=O)N1CC2(CC2)CC1c1ncc(-c2ccc(-c3ccc4cc(-c5cnc(C6C7CCC(C7)N6C(=O)C(NC(=O)OC)C(C)C)[nH]5)ccc4c3)cc2)[nH]1)C(C)C

HCID66620520

未命名化合物

收率 65%

PROCEDURE

实验过程

This compound was prepared using the procedure used to prepare [1-(6-{5-[4-(6-{2-[2-(2-Cyclopropyl-2-methoxycarbonylamino-acetyl)-2-aza-bicyclo[2.2.1]hept-3-yl]-3H-imidazol-4-yl}-naphthalen-2-yl)-phenyl]-1H-imidazol-2-yl}-5-aza-spiro[2.4]heptane-5-carbonyl)-2-methyl-propyl]-carbamic acid methyl ester using 2-Methoxycarbonylamino-3-methyl-butyric acid to provide [1-(3-{5-[6-(4-{2-[5-(2-Methoxycarbonylamino-3-methyl-butyryl)-5-aza-spiro[2.4]hept-6-yl]-3H-imidazol-4-yl}-phenyl)-naphthalen-2-yl]-1H-imidazol-2-yl}-2-aza-bicyclo[2.2.1]heptane-2-carbonyl)-2-methyl-propyl]-carbamic acid methyl ester (0.070 g, 65%) as a white powder.

WORKUP

后处理

customThis compound was prepared

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-1dec6b72fd3846a9b7f790f7c1f0771e
来源数据集: uspto-grants-2012_01
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08088368B2
来源说明: uspto-grants-2012_01

反应 SMILES

[CH3:1][O:2][C:3](=[O:62])[NH:4][CH:5]([C:9]([N:11]1[CH:17]([C:18]2[NH:19][C:20]([C:23]3[CH:28]=[CH:27][C:26]([C:29]4[CH:38]=[CH:37][C:36]5[C:31](=[CH:32][CH:33]=[C:34]([C:39]6[NH:40][C:41]([CH:44]7[CH:49]8[CH2:50][CH:46]([CH2:47][CH2:48]8)[N:45]7[C:51](=[O:61])[CH:52]([CH:58]7[CH2:60][CH2:59]7)[NH:53][C:54]([O:56][CH3:57])=[O:55])=[N:42][CH:43]=6)[CH:35]=5)[CH:30]=4)=[CH:25][CH:24]=3)=[CH:21][N:22]=2)[CH2:16][C:13]2([CH2:15][CH2:14]2)[CH2:12]1)=[O:10])[CH:6]([CH3:8])[CH3:7].COC(NC(C(C)C)C(O)=O)=O>>[CH3:57][O:56][C:54](=[O:55])[NH:53][CH:52]([C:51]([N:45]1[CH:44]([C:41]2[NH:40][C:39]([C:34]3[CH:33]=[CH:32][C:31]4[C:36](=[CH:37][CH:38]=[C:29]([C:26]5[CH:25]=[CH:24][C:23]([C:20]6[NH:19][C:18]([CH:17]7[CH2:16][C:13]8([CH2:14][CH2:15]8)[CH2:12][N:11]7[C:9](=[O:10])[CH:5]([NH:4][C:3]([O:2][CH3:1])=[O:62])[CH:6]([CH3:8])[CH3:7])=[N:22][CH:21]=6)=[CH:28][CH:27]=5)[CH:30]=4)[CH:35]=3)=[CH:43][N:42]=2)[CH:49]2[CH2:50][CH:46]1[CH2:47][CH2:48]2)=[O:61])[CH:58]([CH3:59])[CH3:60]