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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 424017Generated: October 29, 2026

2-Fluoro-4-iodoaniline → 3-Ethyl-5,6-difluoro-N-(2-fluoro-4-iodophenyl)-2-nitroaniline

https://huagongshe.com/reaction/424017

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-Fluoro-4-iodoanilineHCID 185694—
Reactant1-Ethyl-3,4,5-trifluoro-2-nitrobenzeneHCID 59386371—
Product3-Ethyl-5,6-difluoro-N-(2-fluoro-4-iodophenyl)-2-nitroanilineHCID 5938634760%

Reaction Steps

2-Fluoro-4-iodoaniline (2.05 g, 10 mmol) and 1-ethyl-3,4,5-trifluoro-2-nitrobenzene (2.37 g, 10 mmol) were reacted using the condition described in example 1 (Step A) to form the title compound (2.47 g, 60%); m/z=407 [M−1]

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08101799B2
Source datasetuspto-grants-2012_01
ORD IDord-5b2bd463bbc9473a825c7a5db6fa5a7e
Source noteuspto-grants-2012_01